房屋细分电力负荷计算表 (含次要套房或后巷屋)

Electrical Load Calculation for a Sub-division of a Single Family Dwelling... CEC Rule 8-200(2)

CEC 规范 8-200(2) 负荷明细
Minimum ampacity of service feeder...
主房 (SFD)
SFD input
套房 (SS)
SS input
后巷屋 (LWH)
LWH input
备注 (Note)
请输入各单元面积 (平方英尺 Sq.Ft) Area input in Square Feet (Auto converts to m²) 大部分图纸使用平方英尺,系统将自动向下换算为平米。
各单元面积 (平方米 m²) Area input in m² *Area in m²
(1 m² = 10.764 sq.ft)
(1)(a)(i) 首个 90 m² 的基础负荷 (5000 W)a basic load of 5000 W for the first 90 m² 5000 5000 0 *Contractor to provide accurate m² as calculated per info from Building permit.
(1)(a)(ii) 超过 90 m² 的部分,每 90 m² 加 1000 Wan additional 1000 W for each 90 m² or portion thereof in excess 1000 1000 0
(1)(a)(iii) 电暖气负荷 (输入 W)any electric space-heating loads (Section 62) Subject to interlock Rule 8-106(4) in demand app.
(1)(a)(iii) 空调负荷 (输入 W)any AC "Rule 8-106(4)"
(1)(a)(iv) 电炉灶 (填入铭牌瓦数 W)single electric range: 6000 W + 40%-exceeds 12 kW = 6000 W = 6000 W 0 Input plate rating. Auto calculates 6000W + excess.
(1)(a)(v) 即热电热水器/泳池等 (填 100% W)electric tankless water heaters / pools... 100% *To book an inspection... call 311
(1)(a)(vi) 电车充电桩 (填 100% W)electric vehicle charging equipment loads. 100%
(1)(a)(vii) 其他电器总负荷 (填入总瓦数 W) additional loads: electric range provided-25% X (>1500 W), or no electric range provided-100% of (>1500 W) up to 6000 W, + 25% X (>6000 W) = 1250 W = 1250 W 0 Input total wattage. Auto calculates deductions.
(1)(b) 最小电箱容量规范声明 (i) 100 A, exclusive of basement, is 80 m² or more; or (ii) 60 A... is less than 80 m² -- 规范要求底线参考,系统取计算值与底线之较大者 -- CEC Rule minimums.
基础需求总负荷 (不含冷暖)Total calculated demand loads (watts) 13250 W 13250 W 0 W
转换为安培 (W ÷ 240V)Base Amps (used in Demand Application) 55.21 Amps 55.21 Amps 0.00 Amps
CEC Rule 8-200(2) Demand Application (负荷合并计算)
8-200(2)(a) excluding any electric space-heating & air-cond loads: 8-202(3)(a)(i)-100% of calculated load of unit with heaviest load; + (3)(a)(ii)-65% of next two units.


8-200(2)(a)(b). 8-202(3)(b)(c). electric space-heating loads "Section 62, subject to Rule 8-106(4)" and 100% air-conditioning loads.
100% 最大单元: 55.21 Amps
65% 第二单元: 35.89 Amps
65% 第三单元: 0.00 Amps
电暖气总和 (Amps): 0.00
空调总和 (Amps): * 系统按 8-106(4) 自动取冷/暖两者的最大值计入总负荷。 0.00
The size of consumer's service conductors... to be based on the calculated load obtained from Subrule (1)(a)... plus 8-202(3)(b)&(c).

📝 预填默认值业务说明 (基于您提供的图纸与常见卡尔加里房型):